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5v^2-3=417
We move all terms to the left:
5v^2-3-(417)=0
We add all the numbers together, and all the variables
5v^2-420=0
a = 5; b = 0; c = -420;
Δ = b2-4ac
Δ = 02-4·5·(-420)
Δ = 8400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8400}=\sqrt{400*21}=\sqrt{400}*\sqrt{21}=20\sqrt{21}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{21}}{2*5}=\frac{0-20\sqrt{21}}{10} =-\frac{20\sqrt{21}}{10} =-2\sqrt{21} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{21}}{2*5}=\frac{0+20\sqrt{21}}{10} =\frac{20\sqrt{21}}{10} =2\sqrt{21} $
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